Chemical formula of anion in peroxide, superoxide, ozonide of alkali metals :

O_{2}^{-}, O_{2}^{2}, O_{3}^{- 2}

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O_{2}^{- 2}, O_{2}^{-}, O_{3}^{-}

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O_{2}^{- 2}, O_{2}^{- 2}, O_{3}^{-}

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O_{2}^{-}, O_{2}^{- 3}, O_{3}^{- 2}

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Solution

The correct option is B $O_{2}^{- 2}, O_{2}^{-}, O_{3}^{-}$
Chemical formula of anion in peroxide, superoxide, ozonide of alkali metals is $O_{2}^{- 2}, O_{2}^{-}, O_{3}^{-}$ respectively.

Examples include sodium peroxide $N a_{2} O_{2}$ , potassium superoxide $K O_{2}$ and sodium ozonide $N a O_{3}$ .

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Similar questions

The chemical reaction $2 O_{3} \to 3 O_{2}$ involves two elementary steps :
$O_{3} f a s t - - \to O_{2} + O; O + O_{3} S l o w - -- \to 2 O_{2}$
The differential rate law expression will be :

Q. The decomposition of ozone proceeds as

O_{3} \Leftrightarrow O_{2} + O (f a s t) O + O_{3} \to 2 O_{2} (s l o w)

The rate expression should be

The reaction ; $2 O_{3}$ → $3 O_{2}$ , is assigned the following mechanism.

(I) $O_{3} ⇋ O_{2} + O (i i) O_{3} + O s l o w ⇌ 2 O_{2}$

The rate law of the reaction will therefore be

Q. The chemical reaction,

2 O_{3} \to 3 O_{2}

proceeds as follows:

O_{3} ⇌ O_{2} + O

....(fast)

O + O_{3} \to 2 O_{2}

....(slow)

The rate law expression should be:

Q. The correct order of bond length of

O - O

O_{2}, H_{2} O_{2}, O_{3}

is:

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Chemical formula of anion in peroxide, superoxide, ozonide of alkali metals :

The correct option is B O−22,O−2,O−3Chemical formula of anion in peroxide, superoxide, ozonide of alkali metals is O−22,O−2,O−3 respectively. Examples include sodium peroxide Na2O2, potassium superoxide KO2 and sodium ozonide NaO3.