Chlorination of acetaldehyde gives:

H C O O C l

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C H_{3} C O C l

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C C l_{3} C H O

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C_{2} H_{5} C l

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Solution

The correct option is D $C C l_{3} C H O$
$C H_{3} C H O a c e t a l d e h y d e {C l}_{2} / h υ - --- \to C {C l}_{3} C H O t r i c h l o r a c e t a l d e h y d e$
Acetaldehyde on chlorination gives Trichloroacetaldehyde

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