$X P C l_{5} ⟶ C_{2} H_{5} C l$

$Y P C l_{5} ⟶ C H_{3} C O C l$

X and Y are ?

(C_{2} H_{5})_{2} O

and

C H_{3} C O O H

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C_{2} H_{5} I

and

C_{2} H_{5} C H O

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C_{2} H_{5} O H

and

C H_{3} C O O H

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C_{2} H_{5} O H

and

C_{2} H_{5} C H O

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Solution

The correct option is C $C_{2} H_{5} O H$ and $C H_{3} C O O H$
$C_{2} H_{5} O H + P C l_{5} \to C_{2} H_{5} C l + P O C l_{3} + H C l$

$X = C_{2} H_{5} O H$

$C H_{3} C O O H + P C l_{5} \to C H_{3} C O C l + H C l + P O C l_{3}$

$Y = C H_{3} C O O H$

Hence, option C is correct .

Suggest Corrections

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$X + N a \to C + H_{2}$
$B + C \to (C_{2} H_{5})_{2} O + N a C l$

Then A and X respectively are

Complete the following equations and write the names of the products formed.
(i) ${C H}_{3} C O O H$ + NaOH (ii) $C_{2} H_{5} O H$ + $O_{2}$
(iii) ${C H}_{3} C O O H$ + $C_{2} H_{5} O H$

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C H_{3} C O O H, H_{2} O

and

C_{2} H_{5} O H

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C H_{3} C O O H

and write its reaction with

C_{2} H_{5} O H

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Then A and X are respectively

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XPCl5⟶C2H5ClYPCl5⟶CH3COCl X and Y are ?

The correct option is C C2H5OH and CH3COOHC2H5OH+PCl5→C2H5Cl+POCl3+HClX=C2H5OHCH3COOH+PCl5→CH3COCl+HCl+POCl3Y=CH3COOHHence, option C is correct .

$X P C l_{5} ⟶ C_{2} H_{5} C l$

$Y P C l_{5} ⟶ C H_{3} C O C l$

X and Y are ?

The correct option is C $C_{2} H_{5} O H$ and $C H_{3} C O O H$
$C_{2} H_{5} O H + P C l_{5} \to C_{2} H_{5} C l + P O C l_{3} + H C l$

$X = C_{2} H_{5} O H$

$C H_{3} C O O H + P C l_{5} \to C H_{3} C O C l + H C l + P O C l_{3}$

$Y = C H_{3} C O O H$

Hence, option C is correct .