Chlorination of CS 2 in the presence of AlCl 3 gives-A- CCl 4B- CS 2 Cl 2C- CH 4D- CHCl 3

The correct option is A CCl_4CS_2 + 3Cl_2 CCl_4 + S_2 Cl_2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Acidic Buffer Action

Chlorination ...

Question

Chlorination of $C S_{2}$ in the presence of $A l C l_{3}$ gives:

C C l_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C S_{2} C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H C l_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $C C l_{4}$
$C S_{2} + 3 C l_{2} A l C l_{3} - -- \to C C l_{4} + S_{2} C l_{2}$

Suggest Corrections

Similar questions

Q. Chlorination of toluene in the presence of light and heat followed by treatment with aqueous

N a O H

gives:

Q. The chlorination of toluene in the presence of light and heat followed by treatment with aqueous

N a O H

gives:

Q. Benzene reacts with chlorine molecules in presence of ultra-violet light to give a compound

A

which acts as an insectiside.
Benzene on treatment with excess of chlorine in presence of anhydrous

A l C l_{3}

form a chlorinated molecule

B

along with

H C l

.
The sum of total number of atoms present in each of the compound

A

and

B

is:

Tetrachloroethylenedoes not add chlorine quantitatively under ordinary conditions. However, when the same reaction is carried out in presence of aluminium chloride, addition occurs easily. The role of $A l C l_{3}$ is

Chlorobenzene is formed by reaction of chlorine with benzene in the presence of $A l C l_{3}$ . Which of the following species attacks the benzene ring in this reaction?

(a) $C l^{-}$ (b) $C l^{+}$ (c) $A l C l_{3}$ (d) $[A l C l_{4}]^{-}$

Join BYJU'S Learning Program

Chlorination of CS2 in the presence of AlCl3 gives:

The correct option is A CCl4CS2+3Cl2AlCl3−−−→CCl4+S2Cl2

Chlorination of $C S_{2}$ in the presence of $A l C l_{3}$ gives:

The correct option is A $C C l_{4}$
$C S_{2} + 3 C l_{2} A l C l_{3} - -- \to C C l_{4} + S_{2} C l_{2}$