Chlorine has two isotopes of atomic mass units 34.97 and 36.97. The relative abundance of an isotope is 0.755 and 0.245 respectively. Find the average atomic mass of chlorine.

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Solution

Average atomic mass $= (34.97 \times 0.735 + 36.97 \times 0.245) / (0.735 + 0.245)$
$= (25.70295 + 9.05765) / 0.98$
$= 35.47 u$

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Chlorine has two isotopes of atomic mass units 34.97 and 36.97. The relative abundance of an isotope is 0.755 and 0.245 respectively. Find the average atomic mass of chlorine.

Average atomic mass =(34.97×0.735+36.97×0.245)/(0.735+0.245)=(25.70295+9.05765)/0.98=35.47u

Average atomic mass $= (34.97 \times 0.735 + 36.97 \times 0.245) / (0.735 + 0.245)$
$= (25.70295 + 9.05765) / 0.98$
$= 35.47 u$