Question

Chloro compound of Vanadium has only spin magnetic moment of 1.73 BM. This Vanadium chloride has the formula: (at. no. of V = 23)

• A. $VC{l}_4$
• B. $VC{l}_3$
• C. $VC{l}_2$
• D. $VC{l}_5$

Answer 1

The correct option is A $VC{l}_4$

If the magnetic moment is 1.73 BM then the ion is $V^{4+}$ since this has one unpaired electron.

$\mu =\sqrt{n(n+2)}=1.73,n=1$