Choose the correct answer among the alternatives given :
2-Chloro-2methylpropane on reaction with alc. $K O H$ gives X as the product , X is ?

but-2-ene

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2-methylbut-1-ene

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2-methylprop-1-ene

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2-methylbutan-2-ol

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Solution

The correct option is A 2-methylprop-1-ene
When the reaction is carried out with KOH, the reaction will proceed via $S_{N} 2$ pathway. As the polarity of solvent decreases $S_{N} 1$ pathway is not favored. Because stabilization carbocation via salvation is not possible. So via $S_{N} 2$ pathway, complete inversion of configuration occurs. The product formed will be 2-methylprop-1-ene.

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C H_{3} - C H | B r - C H_{3} [a l c K O H] - ----- \to X p e r o x i d e - ---- \to H B r Y a c e t o n e - --- \to N a I Z

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