1
Question
Choose the correct answer among the alternatives given:
In the following reactions,
(i)CH3−CH3|CH−C|OHH−CH3H+/heat−−−−−→A[Major product]+B[Minor product]
(ii)AHBr,dark−−−−−−−−−−−−−→inabsenceofperoxideCMajor product+DMinor product
The major products A and C are respectively?
Choose the correct answer among the alternatives given:
In the following reactions,
(i)CH3−CH3|CH−C|OHH−CH3H+/heat−−−−−→A[Major product]+B[Minor product]
(ii)AHBr,dark−−−−−−−−−−−−−→inabsenceofperoxideCMajor product+DMinor product
The major products A and C are respectively?
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Solution
The correct option is D CH3−C|CH3=CH−CH3 and CH3−Br|C|CH3−CH2−CH3
(i)CH3−CH3|CH−C|OHH−CH3H+/heat−−−−−→A[Majorproduct]+B[Minorproduct]
its dehydration reaction of alcohol that gives mixture of alkene where the major product is the more substituted alkene according to Saytzeff rule and minor product is the less substituted alkene as:
CH3−CH3|CH−C|OHH−CH3H+/heat−−−−−→CH3−C|CH3=CH−CH3[Major product=A]+CH3−C|CH3HCH=CH2[Minor product=B]
(ii)AHBr,dark−−−−−−−−−−−−−→inabsenceofperoxideCMajorproduct+DMinorproduct
Its a addition reaction that follows Markovnikov's rule and H goes to the double bonded C having more number of hydrogen. ThusCH3−C|CH3=CH−CH3+HBr→CH3−Br|C|CH3−CH2−CH3[Major product=C]+CH3−H|C|CH3−Br|CH−CH3[Minor product=D]Therefore A and C are CH3−C|CH3=CH−CH3 and CH3−Br|C|CH3−CH2−CH3
(i)CH3−CH3|CH−C|OHH−CH3H+/heat−−−−−→A[Majorproduct]+B[Minorproduct]
its dehydration reaction of alcohol that gives mixture of alkene where the major product is the more substituted alkene according to Saytzeff rule and minor product is the less substituted alkene as:
CH3−CH3|CH−C|OHH−CH3H+/heat−−−−−→CH3−C|CH3=CH−CH3[Major product=A]+CH3−C|CH3HCH=CH2[Minor product=B]
(ii)AHBr,dark−−−−−−−−−−−−−→inabsenceofperoxideCMajorproduct+DMinorproduct
Its a addition reaction that follows Markovnikov's rule and H goes to the double bonded C having more number of hydrogen. Thus
CH3−C|CH3=CH−CH3+HBr→CH3−Br|C|CH3−CH2−CH3[Major product=C]+CH3−H|C|CH3−Br|CH−CH3[Minor product=D]
Therefore A and C are CH3−C|CH3=CH−CH3 and CH3−Br|C|CH3−CH2−CH3
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