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Modern Periodic Table

Choose the co...

Question

Choose the correct answer from the alternatives given.
Dead burnt plaster is :

A

C a S O_{4}

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B

C a S O_{4} . \frac{1}{2} H_{2} O

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C

C a S O_{4} . H_{2} O

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D

C a S O_{4} .2 H_{2} O

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Solution

The correct option is A $C a S O_{4}$
Anhydrous calcium sulphate, CaSO $_{4}$ is known as 'dead burnt plaster'. It is formed by heating gypsum, $C a S O_{4} .2 H_{2} O$ at a temperature above 393 K.

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Q. Match List - I with List - II for the compositions of substances and select the correct answer using the codes given below the lists.

List - I (Substances)	List - II (Composition)
A. Plaster of Paris	1. $C a S O_{4} .2 H_{2} O$
B. Epsomite	2. $C a S O_{4} . \frac{1}{2} H_{2} O$
C. Kieserite	3. $M g S O_{4} .7 H_{2} O$
D. Gypsum	4. $M g S O_{4} . H_{2} O$
	5. $C a S O_{4}$

Q. Match List - I with List - II for the compositions of substances and select the correct answer using the code given below the list:
List - I List - II
Substances Composition
(A) Plaster of paris (i)

C a S O_{4} \cdot 2 H_{2} O

(B) Epsomite (ii)

C a s O_{4} \cdot \frac{1}{2} H_{2} O

(C) Kieserite (iii)

M a S O_{4} \cdot 7 H_{2} O

(D) Gypsum (iv)

M g S O_{4} \cdot H_{2} O

C a S O_{4}

Q. Match List - I with List - II for the compositions of substances and select the correct answer using the code given below the list:

List -I	List - II
Substances	Composition
(A) Plaster of paris	(i) $C a S O_{4} \cdot 2 H_{2} O$
(B) Epsomite	(ii) $C a S O_{4} \cdot \frac{1}{2} H_{2} O$
(C) Kieserite	(iii) $M g S O_{4} \cdot 7 H_{2} O$
(D) Gypsum	(iv) $M g S O_{4} \cdot H_{2} O$
	(v) $C a S O_{4}$

$C a S O_{4} .2 H_{2} O Δ 120^{\circ} C - ----- \to A - - + 3 H_{2} O . A$ is

Q. Is there any difference btw the uses of

C a S O_{4} .2 H_{2} O

C a S O_{4} . \frac{1}{2} H_{2} O

?

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