Choose the correct answer from the alternatives given.
Find the least number which when divided by 12, 16, 18, 30 leaves remainder 4 in each case but it is completely divisible by 7.

1769

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724

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1444

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2884

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Solution

The correct option is C 2884
The number divided by $12, 16, 1830 i s 720$
$(L C M o f 12, 16, 18, 30)$ .
Required number is of the form $(720 k + 4)$
at $k = 4$
we get $720 \times 4 + 4 = 2884$ which is completely divisible by $7$ .

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