Choose the correct answer from the alternatives given :

Refer to the diagram which shows the synthesis of part of a protein molecule.

Which of the following is the first part of the protein molecule that would be translated from $m R N A_{2}$ ?

A A_{4} - A A_{2} - A A_{7} - A A_{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A A_{6} - A A_{7} - A A_{2} - A A_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A A_{3} - A A_{1} - A A_{6} - A A_{8}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A A_{8} - A A_{5} - A A_{1} - A A_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $A A_{8} - A A_{5} - A A_{1} - A A_{3}$
Given here is the process of translation of the mRNA. Here the translating unit is formed by the tRNA and the ribosomes. The ribosomes then attache to the mRNA and the amino acids are bought by the tRNA. By recognizing the sequence on the mRNA molecule the ribosome starts bonding the amino acids into a chain.
This is the protein formation. The anticodon loop on tRNA has a complementary sequence for the mRNA molecule.

So, the correct option is 'AA8−AA5−AA1−AA3'.

Suggest Corrections

Similar questions

{A A}^{^{'}}, {A A}_{3}^{^{'}}, {A A}_{5}^{^{'}}

{A A}_{7}^{^{'}}

A

{A A}^{^{'}}

{A A}_{3}^{^{'}}

T -

{A A}_{5}^{^{'}}

{A A}_{7}^{^{'}}

a = 6 - \sqrt{35},

(a) a^{2} + \frac{1}{a^{2}}

(b) a^{2} - \frac{1}{a^{2}}

(a) a^{4} - \frac{1}{a^{4}}

A = [\begin{matrix} 0 & - 1 1 & 0 \end{matrix}],

Join BYJU'S Learning Program