Choose the correct answer from the alternatives given. What proportion of the offsprings obtained from cross AABBCC X AaBbCc will be completely heterozygous for all the genes segregated independently?
A
1/8
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B
1/4
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C
1/2
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D
1/16
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Solution
The correct option is B 1/8 Since the 1st parents' genotype is AABBCC, gamete formed will be of only 1 type i.e. ABC. Another parent is heterozygous for all genes. There will be 8 gametes formed and only 1 gamete will be abc. so, only 1 out of 8 progeny formed will be heterozygous for all characters.