Question

Choose the correct answers from the alternatives given.
Find the total surface area of a cube whose volume is equal to the volume of a rectangle solid of sides $11m,22m$ and $44$ m.

• A. $3296m^2$
• B. $2374m^2$
• C. $2904m^2$
• D. $3126m^2$

Answer 1

Answer: (C)

$2904m^2$

Volume of rectangular solid$=(11\times 22\times 44)c{m}^3=10648c{m}^3$

Hence volume of cube $=10648c{m}^3$.

Side of cube$\left(a\right)=(10648{)}^{1/3}cm=22cm$

Hence total surface area $=6a^2=6(22{)}^{2}c{m}^2=2904c{m}^2$