Choose the correct increasing order of density of the following compound.

C_{3} H_{7} C l < C_{3} H_{7} I < C H_{2} C l_{2} < C C l_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{3} H_{7} I < C_{3} H_{7} C l < C H_{2} C l_{2} < C C l_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{3} H_{7} I < C_{3} H_{7} C l < C C l_{4} < C H_{2} C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C C l_{4} < C H_{2} C l_{2} < C_{3} H_{7} I < C_{3} H_{7} C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $C_{3} H_{7} C l < C_{3} H_{7} I < C H_{2} C l_{2} < C C l_{4}$
The density increases with an increase in the number of carbon atoms, halogen atoms and an atomic mass of the halogen atoms.
Densities of some compounds:
$C_{3} H_{7} C l : 0.89, C_{3} H_{7} B r : 1.335, C_{3} H_{7} I : 1.747, C H_{2} C l_{2} : 1.336, C H C l_{3} : 1.489, C C l_{4} : 1.595$ .
So the correct option is A.

Suggest Corrections

Similar questions

C H_{4}, C H_{3} C l, C H_{2} C l_{2}, C H C l_{3}, C C l_{4}

C C l_{4}

C H_{3} C l

C H_{4} = C C l_{4} < C H C l_{3} < C H_{2} C l_{2} < C H_{3} C l

C H_{3} C l

C H_{2} C l_{2}

C H C l_{3}

C C l_{4}

C H_{2} C l_{2}

C C l_{4}

C H_{4}, C H_{3} C l, C H_{2} C l_{2}, C H C l_{3}

C C l_{4}

C H_{4}, C H_{3} C l, C H_{2} C l_{2}, C H C l_{3}

C C l_{4}

Join BYJU'S Learning Program