Question

Choose the correct option and justify your choice:
$\frac{1-{\tan }^2{45}^{\circ }}{1+{\tan }^2{45}^{\circ }}=$

• A. $\tan {90}^{\circ }$
• B. $1$
• C. $\sin {45}^{\circ }$
• D. $0$

Answer 1

The correct option is D $0$

The value of $\frac{1-{\tan }^2{45}^o}{1+{\tan }^2{45}^o}$

$=\frac{1-(1{)}^2}{1-(1{)}^2}$

$=\frac{1-1}{1+1}=\frac{0}{2}=0$