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Byju's Answer
Standard X
Mathematics
Range of Trigonometric Ratios from 0 to 90 Degrees
Choose the co...
Question
Choose the correct option. Justify your choice.
1
+
tan
2
A
1
+
cot
2
A
=
A
sec
2
A
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B
−
1
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C
cot
2
A
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D
tan
2
A
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Solution
The correct option is
D
tan
2
A
The value of
1
+
tan
2
A
1
+
cot
2
A
=
1
+
sin
2
A
cos
2
A
1
+
cos
2
A
sin
2
A
=
cos
2
A
+
sin
2
A
sin
2
A
+
cos
2
A
×
sin
2
A
cos
2
A
=
tan
2
A
Suggest Corrections
4
Similar questions
Q.
tan
2
A/1+tan
2
A + cot
2
A/1+cot
2
A=sec
2
Acos
2
A-2secAcosA
Q.
(
1
+
tan
2
A
1
+
cot
2
A
)
=
tan
2
A
Q.
(
1
+
tan
2
A
1
+
cot
2
A
)
=
(
1
−
tan
2
A
1
−
cot
2
A
)
2
=
tan
2
A
Q.
Prove that
tan
2
A
1
+
tan
2
A
+
cot
2
A
1
+
cot
2
A
=
1
Q.
1
+
tan
2
A
1
+
cot
2
A
=
_____
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Range of Trigonometric Ratios from 0 to 90
MATHEMATICS
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NCERT - Standard X
Range of Trigonometric Ratios from 0 to 90 Degrees
Standard X Mathematics
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