Choose the correct option regarding change in oxidation number of the underlined atom in the following conversion-
$K I - \to K I O_{3} H_{2} S O_{5} + 2 K I \to K_{2} S O_{4} + H_{2} O + I_{2}$

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Solution

In the transformation $K I - \to K I O_{3}$ , the oxidation number of iodine changes from -1 to +5.
Hence, the change in the oxidation number of iodine is +6.
In the transformation, $H_{2} S O_{5} + 2 K I \to K_{2} S O_{4} + H_{2} O + I_{2}$
the oxidation number of iodine changes from -1 to 0.
Hence, the change in the oxidation number of iodine is +1.

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