Question

Choose the correct order of reagents to be added for the following conversion:
$C_6{H}_5{\mathrm{CH}}_2\mathrm{Cl}\stackrel{\left(i\right)}{\to }{C}_6{H}_5{\mathrm{CH}}_2\mathrm{CN}\stackrel{\left(\mathrm{ii}\right)}{\to }{C}_6{H}_5{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{NH}}_2\underset{\Delta }{\overset{\left(\mathrm{iii}\right)}{\to }}{C}_6{H}_5{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{NC}$

• A. $\left(i\right){\mathrm{CHCl}}_3/\mathrm{alc}.\mathrm{KOH},\left(\mathrm{ii}\right)H_2/\mathrm{Pd},\left(\mathrm{iii}\right)\mathrm{KCN}/\mathrm{EtOH}$
• B. $\left(i\right)\mathrm{KCN}/\mathrm{EtOH},\left(\mathrm{ii}\right)H_2/\mathrm{Pd},\left(\mathrm{iii}\right){\mathrm{CHCl}}_3/\mathrm{alc}.\mathrm{KOH}$
• C. $\left(i\right)H_2/\mathrm{Pd},\left(\mathrm{ii}\right),\mathrm{KCN}/\mathrm{HCl}\left(\mathrm{iii}\right){\mathrm{CHCl}}_3/\mathrm{alc}.\mathrm{KOH}$
• D. $\left(i\right)\mathrm{KCN}/\mathrm{HCl},\left(\mathrm{ii}\right){\mathrm{CHCl}}_3/\mathrm{alc}.\mathrm{KOH},\left(\mathrm{iii}\right)H_2/\mathrm{Pd}$

Answer 1

The correct option is B $\left(i\right)\mathrm{KCN}/\mathrm{EtOH},\left(\mathrm{ii}\right)H_2/\mathrm{Pd},\left(\mathrm{iii}\right){\mathrm{CHCl}}_3/\mathrm{alc}.\mathrm{KOH}$

$C_6{H}_5{\mathrm{CH}}_2\mathrm{Cl}\stackrel{\mathrm{KCN}/\mathrm{EtOH}}{\to }{C}_6{H}_5{\mathrm{CH}}_2\mathrm{CN}\stackrel{H_2/\mathrm{Pd}}{\to }{C}_6{H}_5{\mathrm{CH}}_2{\mathrm{CH}}_2{\mathrm{NH}}_2\underset{\Delta }{\overset{{\mathrm{CHCl}}_3/\mathrm{alc}.\mathrm{KOH}}{\to }}{C}_6{H}_5{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{NC}$