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Standard X
Chemistry
Coordinate Covalent Bond
Choose the co...
Question

Choose the correct order of repulsions between bond pairs and lone pairs of electrons.
LP: lone pair of electrons
BP: bond pair of electrons

A
LP - LP > BP - BP > LP - BP
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B
BP - BP > LP - BP > LP - LP
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C
LP - BP > LP - LP > BP - BP
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D
LP - LP > LP - BP > BP - BP
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Solution

The correct option is D LP - LP > LP - BP > BP - BP
∙ The pair of electrons in valence shell of an atom that does not participate in bonding are called lone pair of electrons.

∙ The electrons that are shared between two atoms to form a covalent bond are called bond pair electrons.

∙ The bond pair and lone pair electrons repel each other in a molecule.

∙ The strength of repulsions is in the following order:
lone pair - lone pair repulsions > lone pair - bond pair repulsions > bond pair - bond pair repulsions or LP - LP > LP - BP > BP - BP.

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Q. Give the correct order of initials T or F for the following statements. Use T if statement is true and use F if the statement is false:
(I) The order of repulsion between pair of electrons is lp−lp>lp−bp>bp−bp where lp=lone pair, bp=bond papir
(II) In general, as the number of lone pair of electrons on central atom increases , value of bond angle from normal bond angle also increases.
(III) The number of lone pair on O in H2O is 2 while on N in NH3 is 1.
(IV) The structures of xenon flourides and xenon oxyflourides could not be explained on the basis of VSEPR theory.
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Q. Hybridization is the chemist's attempt to explain the observed molecular shape by constructing hybridized atomic orbitals with the appropriate inter orbital angles. The molecule for which deviation from a normal bond angle is observed, VSEPR theory suggests electron pair repulsive interaction (lp−lp>lp−bp>bp). While from hybridization point of view that is a departure from normal hybridization because the angle between any equivalent hybrid orbitals determines the fraction of s and p characters of the hybrid and vice-versa.
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