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Question
Choose the correct properties for the following molecules.
(I) CH2F2 (II) CHF3 (III) CH3F
Choose the correct properties for the following molecules.
(I) CH2F2 (II) CHF3 (III) CH3F
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Solution
The correct options are
A C−F bond length order: CH3F>CH2F2>CHF3
B C−H bond length order: CH3F>CH2F2>CHF3
C Shape is not perfectly tetrahedral for given compounds.
D Dipole moment is non zero for given compounds.
a. The C−F bond length decreases in the order: CH3F>CH2F2>CHF3
The electronegative F increases the p character in the C−F bond and increases s character in the C−H bond. As the number of F atoms increases,the p-character per C−F bond decreases and hence the bond length decreases. Also s-character in the C−H increases and hence the C-H bond length decreases.
DDSince the molecules have different C−H and C−F bond length, the shapes are not tetrahedral.
d. In each of three compounds, all bonds are not equivalent and their orientations are not symmetrically arranged due to variations in angles. Hence, all are polar molecules.
A C−F bond length order: CH3F>CH2F2>CHF3
B C−H bond length order: CH3F>CH2F2>CHF3
C Shape is not perfectly tetrahedral for given compounds.
D Dipole moment is non zero for given compounds.
a. The C−F bond length decreases in the order: CH3F>CH2F2>CHF3
The electronegative F increases the p character in the C−F bond and increases s character in the C−H bond. As the number of F atoms increases,the p-character per C−F bond decreases and hence the bond length decreases. Also s-character in the C−H increases and hence the C-H bond length decreases.
DDSince the molecules have different C−H and C−F bond length, the shapes are not tetrahedral.
d. In each of three compounds, all bonds are not equivalent and their orientations are not symmetrically arranged due to variations in angles. Hence, all are polar molecules.
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