Question

Choose the number(s) that is/ are divisible by both $3$ and $8.$

• A. $1306$
• B. $1301$
• C. $2088$
• D. $2112$

Answer 1

Answer: (C), (D)

$2112$

Divisibility by 3: A number, whose sum of digits is divisible by 3, is also divisible by 3.

Divisibility by 8: A number, whose last three digits are divisible by 8, is also divisible by 8.

For divisibility by both the numbers, we need to check the conditions individually.

For $1306,$ sum of the digits is $1+3+0+6=10,$ which is not divisible by $3.$

For $1301,$ sum of the digits is $5,$ which is not divisible by $3.$

For $2088,$ sum of the digits is $18,$ which is divisible by $3.$
Also, the last there digits are $088,$ which is divisible by $8.$

Similarly, $2112$ is divisible by both $3$ and $8.$