Chromyl chloride dissolves in $N a O H$ solution to give a yellow solution. This yellow colour is due to:

C r_{2} O_{7}^{2 -}

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C r O_{4}^{2 -}

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C r O_{5}

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C r_{2} O_{3}

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Solution

The correct option is D $C r O_{4}^{2 -}$
When chromyl chloride vapors are passed through a dilute $N a O H$ solution, it turns yellow. This is due to the formation of the chromate ions, i.e., $C r O_{4}^{2 -}$ .

$C r O_{2} C l_{2} + 4 N a O H ⟶ N a_{2} C r O_{4} + 2 N a C l + H_{2} O$

Hence, option B is the correct answer.

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