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Reactivity with Halogens and Hydrogen (Group 2)

Gradual addit...

Question

Gradual addition of potassium iodide solution to an aqueous solution of $B i {(N O_{3})}_{3}$ initially produces a dark brown precipitate which dissolves in excess of $K I$ to give a clear yellow solution. This yellow colour is due to the formation of:

A

K I O_{3}

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B

K I_{3}

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C

B i I_{3}

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D

K_{2} [B i I_{5}]

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Solution

The correct option is C $K I_{3}$
The hydrolysis of $B i (N O_{3})_{3}$ generates nitric acid.
$B i (N O_{3})_{3} + H_{2} O \to [B i (O H) (N O_{3})_{2}] + H N O_{3}$
Nitric acid oxidizes $K I$ to iodine.
$2 H N O_{3} \to H_{2} O + 2 N O_{2} + [O] 2 K I + H_{2} O + [O] \to 2 K O H + I_{2}$
Iodine reacts with potassium iodide to form $K I_{3}$ which gives rise to yellow colour.
$I_{2} + K I \to K I_{3} (Yellow)$
Hence, option C is correct.

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