$C l_{2} (g) + O H^{-} (a q) \to O C l^{-} (a q) + C l^{-} (a q)$
Balance the above reaction using oxidation number method.

3 C l_{2} (g) + 5 O H^{-} (a q) \to O C l^{-} (a q) + C l^{-} (a q) + 2 H_{2} O (l)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C l_{2} (g) + 2 O H^{-} (a q) \to O C l^{-} (a q) + C l^{-} (a q) + H_{2} O (l)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 C l_{2} (g) + 2 O H^{-} (a q) \to O C l^{-} (a q) + 6 C l^{-} (a q) + H_{2} O (l)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 C l_{2} (g) + O H^{-} (a q) \to 5 O C l^{-} (a q) + C l^{-} (a q) + 3 H_{2} O (l)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $C l_{2} (g) + 2 O H^{-} (a q) \to O C l^{-} (a q) + C l^{-} (a q) + H_{2} O (l)$
$0 C l_{2} (g) + O H^{-} (a q) \to O + 1 C l^{-} (a q) + - 1 C l^{-} (a q)$

$n_{f} = (| O . S ._{P r o d u c t} - O . S ._{R e a c t a n t} |) \times number of atom$

$(n_{f})_{O C l^{-}} = | + 1 - 0 | \times 1 = 1$
$(n_{f})_{C l^{-}} = | - 1 - 0 | \times 1 = 1$

Cross multiplying with $n_{f}$ values.

$C l_{2} (g) \to 1 O C l^{-} (a q) + 1 C l^{-} (a q)$

Elements except $O$ and $H$ are already balanced.

Now, balancing oxygen by adding $H_{2} O$

$C l_{2} (g) + H_{2} O (l) \to O C l^{-} (a q) + C l^{-} (a q)$

Balancing hydrogen by adding $H^{+}$
$C l_{2} (g) + H_{2} O (l) \to O C l^{-} (a q) + C l^{-} (a q) + 2 H^{+} (a q)$

For balancing in basic medium adding $2 O H^{-}$ to both sides
$C l_{2} (g) + H_{2} O (l) + 2 O H^{-} (a q) \to O C l^{-} (a q) + C l^{-} (a q) + 2 H^{+} (a q) + 2 O H^{-} (a q)$

$C l_{2} (g) + H_{2} O (l) + 2 O H^{-} (a q) \to O C l^{-} (a q) + C l^{-} (a q) + 2 H_{2} O (l)$

Canceling $H_{2} O$
$C l_{2} (g) + 2 O H^{-} (a q) \to O C l^{-} (a q) + C l^{-} (a q) + H_{2} O (l)$

Balancing charge:

charge in reactant side $= - 2 = - 2$
charge in product side $= - 1 - 1 = - 2$

So the balanced equation is
$C l_{2} (g) + 2 O H^{-} (a q) \to O C l^{-} (a q) + C l^{-} (a q) + H_{2} O (l)$

Suggest Corrections

Similar questions

C l_{2} (g) + O H^{-} (a q) \to O C l^{-} (a q) + C l^{-} (a q)

I_{2} (s) + O {C l}^{-} (a q) ⟶ {I O}_{3}^{-} (a q) + {C l}^{-} (a q)

M n (O H)_{2} (s) + M n O_{4}^{-} (a q) \to M n O_{2} (s)

M n (O H)_{2} (s) + M n O_{4}^{-} (a q) \to M n O_{2} (s)

P t | C l_{2} (g, 0.5 bar) | C l^{-} (aq, 0.5 M) | | C l^{-} (aq, 0.05 M) | | C l_{2} (g, 0.05 bar) | P t

298

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program