$C l_{2}$ is passed into $N H_{3}$ . When $N H_{3}$ is in excess, products are $N H_{4} C l$ and $N_{2}$ .
State whether the given statement is true or false.

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Solution

When $C l_{2}$ is passed into excess $N H_{3}$ , the products are $N H_{4} C l$ and $N_{2}$ .

$8 N H_{3} + 3 C l_{2} ⟶ 6 N H_{4} C l + N_{2}$

But in the presence of excess chlorine, the products formed are $N C l_{3}$ and $H C l$ .

$N H_{3} + 3 C l_{2} ⟶ N C l_{3} + 3 H C l$

Hence, the statement is true.

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