Class Interval
Frequency
0 - 10
10 - 20
20 - 30
30 - 40
40 - 50
4
6
10
16
14
The mean of the following frequency distribution is

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Solution

The correct option is D 31
Mean = $\frac{s u m o f (M e a n o f c l a s s i n t e r v a l \times f r e q u e n c y)}{S u m o f f r e q u e n c y}$

Mean = $\frac{5 \times 4 + 15 \times 6 + 25 \times 10 + 35 \times 16 + 45 \times 14}{4 + 6 + 10 + 16 + 14}$

Mean = $\frac{1550}{50}$ = 31

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Similar questions

Class-interval:	0-10	10-20	20-30	30-40	40-50
No. of workers f:	7	10	15	8	10

Class Interval:	0-10	10-20	20-30	30-40	40-50
Frequency	12	13	25	20	10

Class Interval	0-10	10-20	20-30	30-40	40-50
Frequency	12	16	6	7	9

Class	0-10	10-20	20-30	30-40	40-50
$f$	6	10	13	7	4

Class-intervals	0-10	10-20	20-30	30-40	40-50
Frequency	12	11	14	10	13

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Class Interval	Frequency
0 - 10 10 - 20 20 - 30 30 - 40 40 - 50	4 6 10 16 14