Ac- KOHClCH 2 CHCl 2 alA is-A- CH 2- CCl 2B- CHCl - CHClC- CH - CHD- ClCH 2 CHO

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Nucleophilic Substitution in Alkyl Halides

ac. KOHClCH 2...

Question

$C l C H_{2} C H C l_{2} alc. KOH - ---- \to A$
A is:

C H C l = C H C l

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C H_{2} = C C l_{2}

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C H \equiv C H

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C l C H_{2} C H O

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Solution

The correct option is B $C H_{2} = C C l_{2}$
Base will abstract the most acidic proton.

In alcoholic solution, elimination is favored. The most acidic hydrogen is removed in the elimination by base. Since it is not a strong base, it can not be further dehydrohalogenated.

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Fill up the blanks with suitable reagents to show synthesis of polyvinyl chloride.

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ClCH2CHCl2alc. KOH−−−−−→A A is:

The correct option is B CH2=CCl2Base will abstract the most acidic proton. In alcoholic solution, elimination is favored. The most acidic hydrogen is removed in the elimination by base. Since it is not a strong base, it can not be further dehydrohalogenated.

$C l C H_{2} C H C l_{2} alc. KOH - ---- \to A$
A is:

The correct option is B $C H_{2} = C C l_{2}$
Base will abstract the most acidic proton.

In alcoholic solution, elimination is favored. The most acidic hydrogen is removed in the elimination by base. Since it is not a strong base, it can not be further dehydrohalogenated.