Question

$C{O}_3^{2-}$ and $S{O}_3^{2-}$ cannot be distinguished by:

• A. $H_2{O}_{2}solution$
• B. $limewater$
• C. $C{l}_{2}water$
• D. $Allofthese$

Answer 1

The correct option is B $limewater$

$C{O}_3^{2-}$ and $S{O}_3^{2-}$ cannot be distinguished by lime water as

$CaO+C{O}_3^{2-}+C{O}_3^{2-}\to CaC{O}_3$ (white turbidity)

$CaO+S{O}_3^{2-}\to CaS{O}_3$ (white turbidity)

It cannot be distinguished by $A$ and $C$ as $S{O}_3^{2-}$ is oxidized by $H_2{O}_2$ and $C{l}_2$ but $C{O}_3^{2-}$ cannot be.