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Coefficient o...

Question

Coefficient of kinetic friction between 3 kg and 2 kg block is 0.25. The horizontal table surface is smooth. Find the acceleration of block of mass 10 kg is .(in $m s^{- 2}$ )

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Solution

$a = \frac{100 - 0.25 \times 20 - 0.25 \times 20}{15} = 6$ $\frac{m}{s^{2}}$

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