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Question

# Mass of upper block and lower block kept over the table is 2 kg and 1 kg respectively and coefficient of friction between the blocks is 0.1. Table surface is smooth. The maximum mass m for which all the three blocks move with same acceleration is (g=10 m/s2)

A
1 kg
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B
2/3 kg
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C
1/3 kg
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D
3/4 kg
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Solution

## The correct option is D 3/4 kgDrawing FBDs and writing force equations, T−fr=2a f12=μ×2g=0.1×2×10=2 N ⇒T−2=2a−−(1) f12=1.a=2−−(2) ⇒a=2 m/s2 ⇒T=3a=3×2=6 N mg−T=ma mg−6=m×2 10 m−2 m=6 8 m=6 ⇒m=6/8=3/4 kg

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