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Byju's Answer
Standard VI
Physics
Kinetic Friction
Coefficient o...
Question
Coefficient of kinetic friction between
3
kg
and
2
kg
block is
0.25
. The horizontal table surface is smooth. Find the acceleration
(
in
m/s
2
)
of block of mass
10
kg
.
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Solution
For
10
kg
,
10
g
−
T
2
=
10
a
.
.
.
.
.
(
1
)
For
3
kg
,
T
2
−
(
T
1
+
μ
N
)
=
3
a
T
2
−
T
1
−
0.25
×
2
×
g
=
3
a
T
2
−
T
1
−
5
=
3
a
.
.
.
.
.
.
.
.
.
(
2
)
For
2
kg
,
T
1
−
0.25
×
2
×
g
=
2
a
T
1
−
5
=
2
a
.
.
.
.
.
.
.
(
3
)
By solving equation
(
1
)
,
(
2
)
and
(
3
)
, we get
10
g
−
5
−
5
=
10
a
+
3
a
+
2
a
90
=
15
a
∴
a
=
6
m/s
2
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