wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Coefficient of x5 in the expansion of the product (1+2x)6(1x)7 is:

A
115
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
165
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
171
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
none of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 171
We have,
(1+2x)6(1x)7=[1+6C1(2x)+6C2(2x)2+...+6C6(2x)6]×[17C1x+7C2x27C3x3+...7C6x7]

(1+2x)6(1x)7=(1+12x+60x2+160x3+240x4+192x5+..)×(17x+21x235x3+35x421x5+...)

Coefficient of x5 in the product

=1(21)+12(35)+60(35)+160(21)+240(7)+192(1)
=21+4202100+33601680+192=171

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Binomial Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon