The correct option is C Metal metaborates
Borax on strong heating loses its water of crystallization and then shrinks forming a glassy bead of sodium metaborate (NaBO2) and boric anhydride (B2O3) as shown in reaction given below:
Na2B4O7.10H2O→Na2B4O7+10H2O
Na2B4O7740oC⟶2NaBO2+B2O3
CuO+B2O3→Cu(BO2)2 blue bead
Boric anhydride, being non-voltile displaces more volatile acidic oxides and combine with basic oxides present to form metaborates which are identified through their characteristic colours.