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Reaction with Metals

Colourless sa...

Question

Colourless salt $(A) dil. HCl - ----- \to$ White precipitate (B)
Here, $(A)$ is ${P b ({N O}_{3})}_{2}$ and $(B)$ is ${P b C l}_{2}$ .
If true enter 1, else enter 0.

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Solution

The colourless salt $(A)$ is ${P b ({N O}_{3})}_{2}$ . It reacts with dilute $H C l$ to form a white precipitate of $(B)$ which is ${P b C l}_{2}$ .
${P b ({N O}_{3})}_{2} + 2 H C l \to {P b C l}_{2} + 2 H N O_{3}$

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{B a C l}_{2}

gives white precipitate with an aqueous solution of a salt. The acid radical is either

{S O}_{3}^{2 -}

{S O}_{4}^{2 -}

If true enter 1, else enter 0.

Q. If true enter 1, else enter 0.

P b {({N O}_{3})}_{2} ⟶ P b O + {N O}_{2} + O_{2}

The above reaction is not a disproportionation reaction.

Q. The major product formed when

P b_{3} O_{4}

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