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Werner's Coordination Theory

BaCl 2 gives ...

Question

${B a C l}_{2}$ gives white precipitate with an aqueous solution of a salt. The acid radical is either ${S O}_{3}^{2 -}$ or ${S O}_{4}^{2 -}$ .
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Solution

The acid radical is either ${S O}_{3}^{2 -}$ or ${S O}_{4}^{2 -}$ .
Barium chloride reacts with these radicals to form a white precipitate of either barium sulphite or barium sulphate.
$B a C l_{2} + {S O}_{3}^{2 -} \to B a S O_{3} + 2 C l^{-}$
$B a C l_{2} + {S O}_{4}^{2 -} \to B a S O_{4} + 2 C l^{-}$

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Similar questions

Q. State True or False.

{B a C l}_{2}

gives white precipitate with an aqueous solution of a salt. The acid radical is

{S O}_{3}^{2 -}

Q. A light bluish green crystalline compound responds to the following tests:
(i) Its aqueous solution gives a brown precipitate or colouration with alkaline

K_{2} [{H g I}_{4}]

solution.
(ii) Its aqueous solution gives a blue colour with

K_{3} [{F e (C N)}_{6}]

solution.
(iii) Its solution in hydrochloric acid gives a white precipitate with

{B a C l}_{2}

solution. The molecular formula of the compound is

F e S O_{4} . (N H_{4})_{2} S O_{4} . 6 H_{2} O

If the given statement is true enter 1 else enter 0.

Q. If true enter 1, else enter 0.
The gas liberated on heating a mixture of two salts with

N a O H

, gives a reddish brown precipitate with an alkaline solution of

K_{2} {H g I}_{4}

. The aqueous solution of the mixture on treatment with

{B a C l}_{2}

gives a white precipitate which is sparingly soluble in conc.

H C l

. On heating the mixture with

K_{2} {C r}_{2} O_{7}

H_{2} {S O}_{4}

, red vapours (A) are produced. The aqueous solution of the mixture gives a deep blue colouration (B) with potassium ferricyanide solution. The radicals in the given mixture are

F e^{2 +}, N H_{4}^{+}; S O_{4}^{2 +}, C l^{-}

C r O_{2} C l_{2}

B a C l_{2}

is added to an aqueous salt solution, a white precipitate is obtained. The anion among

C O_{3}^{2 -}, S O_{3}^{2 -}

S O_{4}^{2 -}

that was present in the solution can be:

Q. Colourless salt

(A) dil. HCl - ----- \to

White precipitate (B)
Here,

(A)

{P b ({N O}_{3})}_{2}

(B)

{P b C l}_{2}

.
If true enter 1, else enter 0.

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