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Question

# Column -I Column-II A. 2s (P) n=4,l=2,m=0 B. 2pz (Q)n=4,l=2,m=âˆ’2 or +2 C. 4dx2âˆ’y2 (R) n=2,l=1,m=0 D. 4d2z (S) n=2,l=0,m=0 Match the column -I with column -II

A
A S, B R, C Q, D P
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B
A Q, B P, C S, D R
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C
A R, B S, C P, D Q
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D
A S, B R, C P, D Q
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Solution

## The correct option is A A −S, B− R, C− Q, D− PWe know that, n = Principal quantum number which represents the energy level of the orbital. l= Azimuthal quantum number which have the value n−1 m= magnetic quantum number which have the value −l to +l For, 2s⇒n=2,l=0,m=02pz⇒n=2,l=1,m=04dx2−y2⇒n=4,l=2,m=−2 or+24d2z⇒n=4,l=2,m=0

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