A) The given velocity of the object is of form : v=c1√c2−x2 where c1 and c2 are positive constants. This expression is similar to that of velocity of particle in simple harmonic motion that is v=ω√A2−x2 where ω (angular frequency) and A (amplitude) are positive constants. Therefore, option 1.
B) From the equation v=−kx, it can be concluded that if v=0 then x=0 that is object comes to rest at x=0. Thus, object starting from negative x value comes to rest at x=0, it's velocity (hence kinetic energy) decreases with time. Therefore, option 2 and 3.
C) From the reference frame of the observer in the elevator an constant force (pseudo force) acts on the object. Hence the motion of the object will remain simple harmonic. Therefore, option 1.
D) The velocity of the object =2√GMeR=√2√2GMeR=√2ve
where ve is escape velocity.
As other forces are neglected the direction of motion of an object does not change and speed of the object keeps on decreasing. Therefore, option 2 and 3.