Column-I-orbital, Column-II-nodal planes, Column-III-Plots

The only correct combination for an orbital having zero angular node is:

(II) (ii) (Q)

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(II) (iii) (R)

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(I) (iv) (P)

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(I) (iv) (R)

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Solution

The correct option is D
(I) (iv) (R)

Radial/spherical nodes = (n - l - 1)
Angular/planar nodes = l
Total nodes = (n - 1)

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