Column-I: Subshell Column-II: Number of spherical nodes Column-III: Radial plot

The only correct combination for the last electron of $C l^{-}$ is:

(IV) (i) (R)

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(IV) (iv) (P)

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(III) (iii) (Q)

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(II) (ii) (P)

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Solution

The correct option is A
(IV) (i) (R)

$C l^{-} : 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}$

For last electron, subshell is 3p.

Number of spherical nodes $= n - l - 1$

= 3 - 1 - 1 = 1

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Column-I: Subshell Column-II: Number of spherical nodes Column-III: Radial plot The only correct combination for the last electron of Cl− is:

The correct option is A (IV) (i) (R) Cl−:1s2 2s2 2p6 3s2 3p6 For last electron, subshell is 3p. Number of spherical nodes =n−l−1 = 3 - 1 - 1 = 1

Column-I: Subshell Column-II: Number of spherical nodes Column-III: Radial plot

The only correct combination for the last electron of $C l^{-}$ is:

The correct option is A
(IV) (i) (R)

$C l^{-} : 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}$

For last electron, subshell is 3p.

Number of spherical nodes $= n - l - 1$

= 3 - 1 - 1 = 1