Combustion of glucose takes place according to the equation: C6H12O6+6O2→6CO2+6H2O,△H=−72kcal The energy required for production of 1.6g of glucose is [molecular mass of glucose is 180gm]
A
0.064kcal
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B
0.64kcal
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C
6.4kcal
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D
64kcal
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Solution
The correct option is A0.64kcal Formation of glucose will be the given by reaction taking place in reverse direction. 6CO2+6H2O+72Cal→C6H12O6+6O2 For production of 180gm of glucose, heat energy is 72kcals.
number of moles of glucose to be produced
=1.6180 So required heat for 1.6gm of glucose =72180×1.6=0.64kcal