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Question

Combustion of glucose takes place according to the equation:
C6H12O6+6O26CO2+6H2O,H=72 kcal
The energy required for production of 1.6 g of glucose is [molecular mass of glucose is 180 gm]

A
0.064 kcal
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B
0.64 kcal
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C
6.4 kcal
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D
64 kcal
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Solution

The correct option is A 0.64 kcal
Formation of glucose will be the given by reaction taking place in reverse direction.
6CO2+6H2O+72 CalC6H12O6+6O2
For production of 180 gm of glucose, heat energy is 72 k cals.
number of moles of glucose to be produced
=1.6180
So required heat for 1.6 gm of glucose
=72180×1.6=0.64 kcal
Hence, option B is correct

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