Question

Comment on each of the following observations:

(a) $E^{\circ }$ for the reaction, $M^{2+}\left(aq\right)+2e^{-}\to M\left(s\right)$ is nearly constant $(M=Ca,Sr,Ba).$

(b) LiF is least soluble among the fluorides of alkali metals.

• A. (a) is correct, (b) is incorrect
• B. (a) is incorrect, (b) is correct
• C. Both (a) and (b) are correct
• D. None of these

Answer 1

Answer: (C)

Both (a) and (b) are correct

(a) $E^{\circ }$ for the reaction, $M^{2+}\left(aq\right)+2e^{-}\to M\left(s\right)$ is nearly constant $(M=Ca,Sr,Ba).$

(b) LiF is least soluble among the fluorides of alkali metals.

Both the statements are correct because the electrode potentials of all IIA group are same( Ca, Sr, Ba) loses two electrons and will give corresponding alkalies and LiF is least soluble among the fluorides of alkali metals because it is more covalent in nature.

So both a & b are correct statements.

Hence option C is correct.