Comment on the nature of the roots of the equation 2x2–6x+8=0
Real and equal
Real and unequal
Imaginary
None of the above
Step 1:- Given: 2x2–6x+8=0, ⇒ a=2,b=−6,c=8 D=(−6)2–4(2)(8)=36−64=−28. [ D=b2−4ac] Step 2:- Since D<0, the roots are imaginary.