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Molarity

Commercial " ...

Question

Commercial " $11.2 v o l u m e$ " of $H_{2} O_{2}$ solution has a molarity of :

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0.5

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11.2

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1.12

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Solution

The correct option is A 1
The expression for the molarity is $\frac{" x " v o l u m e}{11.2} = \frac{11.2}{11.2} = 1$
Thus, the commercial "11.2 volume" $H_{2} O_{2}$ solution has a molarity of 1 M.

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