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Molarity

H 2 O 2 is ...

Question

$H_{2} O_{2}$ is sold as a solution of approximately $5.0 g H_{2} O_{2}$ per $100 m l$ of the solution the molecular mass of $H_{2} O_{2}$ is $34 .$ The molarity of this solution is approximately:

1.15 M

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1.5 M

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3.0 M

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3.4 M

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Solution

The correct option is A $1.15 M$
Molarity of compound $= \frac{M a s s o f s o l u t e}{M o l a r m a s s} \times \frac{1000}{V (i n m L)}$
Here, Molarity of $H_{2} O_{2} = \frac{5}{34} \times \frac{1000}{100} = \frac{50}{34} = 1.5$ $M$
Molarity of solution $= 1.5$ $M$

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