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Molarity

5.0 g of H2...

Question

$5.0 g$ of $H_{2} O_{2}$ is present in $100 m L$ of the solution. The molecular mass of $H_{2} O_{2}$ is $34$ . The molarity of the solution is:

1.5 M

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0.15 M

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3.0 M

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50 M

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Solution

The correct option is A $1.5 M$
Weight of $H_{2} O_{2}$ $= 5$ grams

Molecular weight of $H_{2} O_{2}$ $= 34$

Volume of $H_{2} O_{2}$ $= 100$ ml

$M = \frac{Weight \times 1000}{Molecular weight \times Volume (in ml)}$

$= \frac{5 \times 1000}{34 \times 100} = 1.47 M$ .
.
Hence option A is correct.

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