Question

Common Data for Q 6.124 and Q.6.125
Data for plain milling operation are given below:
Length of work piece = 200 mm,
Cutter speed = 100 rpm,
Feed = 200 mm/min, Depth of cut = 2 mm,
Tota clearance (entry and exit) = 5 mm

Mean un-deformed chip thickness (in microns)

• A. 142
• B. 100
• C. 71
• D. 50

Answer 1

The correct option is C 71

$t_{avg}=\frac{t_{max}+t_{min}}{2}$

$=\frac{t_{max}}{2}=\frac{f}{Nz}\sqrt{\frac{d}{D}}=\frac{200}{4\times 100}\sqrt{\frac{2}{100}}$

$=0.0707mm=71mm$