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Question

# Common Data: In an orthogonal machining operation: Uncut thickness =0.5mm Cutting speed =20m/min Rake angle =15o Width of cut =5mm Chip thickness =07mm Thrust force =200N Cutting force =1200N Assume Merchant's theory. The coefficient of friction at the tool-chip interface is

A
0.23
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B
0.46
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C
0.85
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D
0.95
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Solution

## The correct option is B 0.46We know that μ=FN=FCsinα+FTcosαFCcosα−FTsinα =1200sin15o+200cos15o1200cos15o−200sin15o μ=FN=FCsinα+FTcosαFCcosα−FTsinα =310.6+193.21159.1−51.76 =0.46

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