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Question

Common Data:
In an orthogonal machining operation:
Uncut thickness =0.5mm
Cutting speed =20m/min
Rake angle =15o
Width of cut =5mm
Chip thickness =07mm
Thrust force =200N
Cutting force =1200N
Assume Merchant's theory.

The coefficient of friction at the tool-chip interface is


A
0.23
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B
0.46
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C
0.85
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D
0.95
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Solution

The correct option is B 0.46
We know that

μ=FN=FCsinα+FTcosαFCcosαFTsinα

=1200sin15o+200cos15o1200cos15o200sin15o

μ=FN=FCsinα+FTcosαFCcosαFTsinα

=310.6+193.21159.151.76

=0.46

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