Compare bond angles for the following molecules :

x > y

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y > x

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x = y

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none of these

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Solution

The correct option is A $x > y$
Oxygen is more electronegative than sulphur. Hence, the bond pairs of electrons are closer in $O_{2} F_{2}$ than in $S_{2} F_{2}$
. This results in greater repulsion between bond pair electrons in $O_{2} F_{2}$ than in $S_{2} F_{2}$ .
hence, the angle in $O_{2} F_{2}$ is greater than the bond angle in $S_{2} F_{2}$ .

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