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Question

Compare the bond lengths (x and y) in the following molecules:

A
x>y
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B
y>x
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C
x=y
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D
None of these
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Solution

The correct option is B y>x
The peripheral atoms in both cases are O and F, out of which F is more electronegative. F will want to combine with the orbital that has less s-character.

In the second molecule (IOF3), 3 flourine atoms are present. Therefore, the oxygen atom will combine with orbitals having more s-character.

In the first molecule (IO2F2), 2 flourine atoms are present. Therefore, the two oxygens will combine with orbitals having less s-character than in IOF3.
bond length1% s character

Thus, the bond length in IO2F2 is greater than that in IOF3.

i.e y>x.

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