Question

Compare the quadratic equation $\sqrt{3}{x}^2+2\sqrt{3}=0toa{x}^2+bx+c=0$ and find the value of discriminant and hence write the nature of the roots.

Answer 1

If we compare the quadratic equation $\sqrt{3}{x}^2+2\sqrt{3}=0toa{x}^2+bx+c=0$.

Then we get, $a=\sqrt{3},b=0,c=2\sqrt{3}$.

Now discriminant $=b^2-4ac=0^2-4\times \sqrt{3}\times 2\sqrt{3}=-24.$

Since the discriminant is $<0$, so the roots of the given equation are imaginary.